Base | Representation |
---|---|
bin | 100101100100100001… |
… | …100010101011001011 |
3 | 10212010110010022101212 |
4 | 211210201202223023 |
5 | 1130104323020133 |
6 | 30311004203335 |
7 | 2625456466265 |
oct | 454441425313 |
9 | 125113108355 |
10 | 40341220043 |
11 | 16121626783 |
12 | 799a23954b |
13 | 3a5b983307 |
14 | 1d49a30b35 |
15 | 10b1939148 |
hex | 964862acb |
40341220043 has 2 divisors, whose sum is σ = 40341220044. Its totient is φ = 40341220042.
The previous prime is 40341220021. The next prime is 40341220061. The reversal of 40341220043 is 34002214304.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40341220043 - 212 = 40341215947 is a prime.
It is not a weakly prime, because it can be changed into another prime (40341220063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20170610021 + 20170610022.
It is an arithmetic number, because the mean of its divisors is an integer number (20170610022).
Almost surely, 240341220043 is an apocalyptic number.
40341220043 is a deficient number, since it is larger than the sum of its proper divisors (1).
40341220043 is an equidigital number, since it uses as much as digits as its factorization.
40341220043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 23.
Adding to 40341220043 its reverse (34002214304), we get a palindrome (74343434347).
The spelling of 40341220043 in words is "forty billion, three hundred forty-one million, two hundred twenty thousand, forty-three".
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