Base | Representation |
---|---|
bin | 111010101110000110000… |
… | …011010101011100000011 |
3 | 112021202121122120100112010 |
4 | 322232012003111130003 |
5 | 1012103114131442011 |
6 | 12325431143504003 |
7 | 564351411136164 |
oct | 72560603253403 |
9 | 15252548510463 |
10 | 4035223312131 |
11 | 13163683a8390 |
12 | 552078158003 |
13 | 23369b37956b |
14 | dd43d37976b |
15 | 6ee7344c1a6 |
hex | 3ab860d5703 |
4035223312131 has 16 divisors (see below), whose sum is σ = 5923263582720. Its totient is φ = 2423153279520.
The previous prime is 4035223312093. The next prime is 4035223312193. The reversal of 4035223312131 is 1312133225304.
It is not a de Polignac number, because 4035223312131 - 218 = 4035223049987 is a prime.
It is a super-2 number, since 2×40352233121312 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4035223312231) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 560911515 + ... + 560918708.
It is an arithmetic number, because the mean of its divisors is an integer number (370203973920).
Almost surely, 24035223312131 is an apocalyptic number.
4035223312131 is a deficient number, since it is larger than the sum of its proper divisors (1888040270589).
4035223312131 is a wasteful number, since it uses less digits than its factorization.
4035223312131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1121830346.
The product of its (nonzero) digits is 12960, while the sum is 30.
Adding to 4035223312131 its reverse (1312133225304), we get a palindrome (5347356537435).
The spelling of 4035223312131 in words is "four trillion, thirty-five billion, two hundred twenty-three million, three hundred twelve thousand, one hundred thirty-one".
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