Base | Representation |
---|---|
bin | 100101100101111101… |
… | …101001111001101101 |
3 | 10212012010120002122122 |
4 | 211211331221321231 |
5 | 1130132013220033 |
6 | 30313225522325 |
7 | 2626201646255 |
oct | 454575517155 |
9 | 125163502578 |
10 | 40365366893 |
11 | 16134219655 |
12 | 79a63433a5 |
13 | 3a639890a7 |
14 | 1d4cd18965 |
15 | 10b3b08a98 |
hex | 965f69e6d |
40365366893 has 2 divisors, whose sum is σ = 40365366894. Its totient is φ = 40365366892.
The previous prime is 40365366841. The next prime is 40365366901. The reversal of 40365366893 is 39866356304.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 35977364329 + 4388002564 = 189677^2 + 66242^2 .
It is a cyclic number.
It is not a de Polignac number, because 40365366893 - 210 = 40365365869 is a prime.
It is a super-3 number, since 3×403653668933 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40365366193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20182683446 + 20182683447.
It is an arithmetic number, because the mean of its divisors is an integer number (20182683447).
Almost surely, 240365366893 is an apocalyptic number.
It is an amenable number.
40365366893 is a deficient number, since it is larger than the sum of its proper divisors (1).
40365366893 is an equidigital number, since it uses as much as digits as its factorization.
40365366893 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8398080, while the sum is 53.
The spelling of 40365366893 in words is "forty billion, three hundred sixty-five million, three hundred sixty-six thousand, eight hundred ninety-three".
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