Base | Representation |
---|---|
bin | 10010010110110010110100… |
… | …00011100010011011101001 |
3 | 12021220220201000021110001112 |
4 | 21023121122003202123221 |
5 | 20242322234030242323 |
6 | 221503412403000105 |
7 | 11334214350530141 |
oct | 1113313203423351 |
9 | 167826630243045 |
10 | 40365613524713 |
11 | 11952a62561654 |
12 | 463b162369035 |
13 | 196a5cbb349b9 |
14 | 9d79c5839921 |
15 | 4a0007875178 |
hex | 24b65a0e26e9 |
40365613524713 has 2 divisors, whose sum is σ = 40365613524714. Its totient is φ = 40365613524712.
The previous prime is 40365613524589. The next prime is 40365613524773. The reversal of 40365613524713 is 31742531656304.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 38500386897424 + 1865226627289 = 6204868^2 + 1365733^2 .
It is a cyclic number.
It is not a de Polignac number, because 40365613524713 - 226 = 40365546415849 is a prime.
It is not a weakly prime, because it can be changed into another prime (40365613524773) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20182806762356 + 20182806762357.
It is an arithmetic number, because the mean of its divisors is an integer number (20182806762357).
Almost surely, 240365613524713 is an apocalyptic number.
It is an amenable number.
40365613524713 is a deficient number, since it is larger than the sum of its proper divisors (1).
40365613524713 is an equidigital number, since it uses as much as digits as its factorization.
40365613524713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5443200, while the sum is 50.
The spelling of 40365613524713 in words is "forty trillion, three hundred sixty-five billion, six hundred thirteen million, five hundred twenty-four thousand, seven hundred thirteen".
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