Base | Representation |
---|---|
bin | 10010010111110111100101… |
… | …11010101111000000100011 |
3 | 12022001110000022221111120022 |
4 | 21023323302322233000203 |
5 | 20243423344143304342 |
6 | 221532400351504055 |
7 | 11336662360345523 |
oct | 1113736272570043 |
9 | 168043008844508 |
10 | 40402537869347 |
11 | 11967690376255 |
12 | 464634822802b |
13 | 1970c34934034 |
14 | 9d96c9749683 |
15 | 4a0e693219d2 |
hex | 24bef2eaf023 |
40402537869347 has 2 divisors, whose sum is σ = 40402537869348. Its totient is φ = 40402537869346.
The previous prime is 40402537869263. The next prime is 40402537869349. The reversal of 40402537869347 is 74396873520404.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40402537869347 - 216 = 40402537803811 is a prime.
Together with 40402537869349, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 40402537869347.
It is not a weakly prime, because it can be changed into another prime (40402537869349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20201268934673 + 20201268934674.
It is an arithmetic number, because the mean of its divisors is an integer number (20201268934674).
Almost surely, 240402537869347 is an apocalyptic number.
40402537869347 is a deficient number, since it is larger than the sum of its proper divisors (1).
40402537869347 is an equidigital number, since it uses as much as digits as its factorization.
40402537869347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 121927680, while the sum is 62.
The spelling of 40402537869347 in words is "forty trillion, four hundred two billion, five hundred thirty-seven million, eight hundred sixty-nine thousand, three hundred forty-seven".
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