Base | Representation |
---|---|
bin | 100101101000001101… |
… | …111110111111100001 |
3 | 10212021202202022200112 |
4 | 211220031332333201 |
5 | 1130221204431032 |
6 | 30321100501105 |
7 | 2630141356613 |
oct | 455015767741 |
9 | 125252668615 |
10 | 40403202017 |
11 | 16153610752 |
12 | 79b6b4a795 |
13 | 3a6b775439 |
14 | 1d53d66db3 |
15 | 10b70ce1b2 |
hex | 96837efe1 |
40403202017 has 2 divisors, whose sum is σ = 40403202018. Its totient is φ = 40403202016.
The previous prime is 40403201989. The next prime is 40403202029. The reversal of 40403202017 is 71020230404.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 38582387776 + 1820814241 = 196424^2 + 42671^2 .
It is a cyclic number.
It is not a de Polignac number, because 40403202017 - 212 = 40403197921 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 40403201983 and 40403202001.
It is not a weakly prime, because it can be changed into another prime (40403202097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20201601008 + 20201601009.
It is an arithmetic number, because the mean of its divisors is an integer number (20201601009).
Almost surely, 240403202017 is an apocalyptic number.
It is an amenable number.
40403202017 is a deficient number, since it is larger than the sum of its proper divisors (1).
40403202017 is an equidigital number, since it uses as much as digits as its factorization.
40403202017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 23.
The spelling of 40403202017 in words is "forty billion, four hundred three million, two hundred two thousand, seventeen".
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