Base | Representation |
---|---|
bin | 1011110000100111001… |
… | …01001011111110100001 |
3 | 1102121221022121010121221 |
4 | 11320103211023332201 |
5 | 23110001143110223 |
6 | 505342010215041 |
7 | 41122604404036 |
oct | 5702345137641 |
9 | 1377838533557 |
10 | 404055441313 |
11 | 1463a4843497 |
12 | 66385424481 |
13 | 2c1438a1a64 |
14 | 157b0a2938d |
15 | a79c970b5d |
hex | 5e1394bfa1 |
404055441313 has 2 divisors, whose sum is σ = 404055441314. Its totient is φ = 404055441312.
The previous prime is 404055441311. The next prime is 404055441319. The reversal of 404055441313 is 313144550404.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 391290283024 + 12765158289 = 625532^2 + 112983^2 .
It is a cyclic number.
It is not a de Polignac number, because 404055441313 - 21 = 404055441311 is a prime.
Together with 404055441311, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (404055441311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202027720656 + 202027720657.
It is an arithmetic number, because the mean of its divisors is an integer number (202027720657).
Almost surely, 2404055441313 is an apocalyptic number.
It is an amenable number.
404055441313 is a deficient number, since it is larger than the sum of its proper divisors (1).
404055441313 is an equidigital number, since it uses as much as digits as its factorization.
404055441313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 57600, while the sum is 34.
Adding to 404055441313 its reverse (313144550404), we get a palindrome (717199991717).
The spelling of 404055441313 in words is "four hundred four billion, fifty-five million, four hundred forty-one thousand, three hundred thirteen".
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