4041255433 has 4 divisors (see below), whose sum is σ = 4042042128. Its totient is φ = 4040468740.

The previous prime is 4041255409. The next prime is 4041255467. The reversal of 4041255433 is 3345521404.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4041255433 - 2²⁵ = 4007701001 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4041255395 and 4041255404.

It is not an unprimeable number, because it can be changed into a prime (4041255133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385591 + ... + 395932.

It is an arithmetic number, because the mean of its divisors is an integer number (1010510532).

Almost surely, 2^4041255433 is an apocalyptic number.

It is an amenable number.

4041255433 is a deficient number, since it is larger than the sum of its proper divisors (786695).

4041255433 is an equidigital number, since it uses as much as digits as its factorization.

4041255433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 786694.

The product of its (nonzero) digits is 28800, while the sum is 31.

The square root of 4041255433 is about 63570.8693742661. The cubic root of 4041255433 is about 1592.8398062360.

Adding to 4041255433 its reverse (3345521404), we get a palindrome (7386776837).

The spelling of 4041255433 in words is "four billion, forty-one million, two hundred fifty-five thousand, four hundred thirty-three".