Base | Representation |
---|---|
bin | 10010011000001101001000… |
… | …01100110100100000110111 |
3 | 12022002112212021002220122021 |
4 | 21030012210030310200313 |
5 | 20244121040120043221 |
6 | 221541552053414011 |
7 | 11340552060653554 |
oct | 1114064414644067 |
9 | 168075767086567 |
10 | 40414102112311 |
11 | 1197158505a144 |
12 | 464863503a307 |
13 | 1972058717a55 |
14 | 9da0a5535a2b |
15 | 4a13e46b9041 |
hex | 24c1a4334837 |
40414102112311 has 2 divisors, whose sum is σ = 40414102112312. Its totient is φ = 40414102112310.
The previous prime is 40414102112243. The next prime is 40414102112323. The reversal of 40414102112311 is 11321120141404.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40414102112311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40414102112381) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20207051056155 + 20207051056156.
It is an arithmetic number, because the mean of its divisors is an integer number (20207051056156).
Almost surely, 240414102112311 is an apocalyptic number.
40414102112311 is a deficient number, since it is larger than the sum of its proper divisors (1).
40414102112311 is an equidigital number, since it uses as much as digits as its factorization.
40414102112311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 40414102112311 its reverse (11321120141404), we get a palindrome (51735222253715).
The spelling of 40414102112311 in words is "forty trillion, four hundred fourteen billion, one hundred two million, one hundred twelve thousand, three hundred eleven".
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