Base | Representation |
---|---|
bin | 111010110011111000001… |
… | …011111000111000110001 |
3 | 112022100122102102111112011 |
4 | 322303320023320320301 |
5 | 1012203323334440101 |
6 | 12332335253402521 |
7 | 564661323520141 |
oct | 72637013707061 |
9 | 15270572374464 |
10 | 4041433124401 |
11 | 1318a64703242 |
12 | 55330b939441 |
13 | 23414aa568aa |
14 | dd86bda2921 |
15 | 701d86cb751 |
hex | 3acf82f8e31 |
4041433124401 has 2 divisors, whose sum is σ = 4041433124402. Its totient is φ = 4041433124400.
The previous prime is 4041433124383. The next prime is 4041433124413. The reversal of 4041433124401 is 1044213341404.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4036277884401 + 5155240000 = 2009049^2 + 71800^2 .
It is a cyclic number.
It is not a de Polignac number, because 4041433124401 - 27 = 4041433124273 is a prime.
It is not a weakly prime, because it can be changed into another prime (4041433128401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2020716562200 + 2020716562201.
It is an arithmetic number, because the mean of its divisors is an integer number (2020716562201).
Almost surely, 24041433124401 is an apocalyptic number.
It is an amenable number.
4041433124401 is a deficient number, since it is larger than the sum of its proper divisors (1).
4041433124401 is an equidigital number, since it uses as much as digits as its factorization.
4041433124401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 4041433124401 its reverse (1044213341404), we get a palindrome (5085646465805).
The spelling of 4041433124401 in words is "four trillion, forty-one billion, four hundred thirty-three million, one hundred twenty-four thousand, four hundred one".
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