Base | Representation |
---|---|
bin | 111010110100100001001… |
… | …100101111001111101011 |
3 | 112022102102101012000111122 |
4 | 322310201030233033223 |
5 | 1012211231012303112 |
6 | 12332531433445455 |
7 | 565014350261111 |
oct | 72644114571753 |
9 | 15272371160448 |
10 | 4042121212907 |
11 | 1319288057328 |
12 | 55348227088b |
13 | 23422a48535b |
14 | dd8d5519ab1 |
15 | 70228ce9872 |
hex | 3ad2132f3eb |
4042121212907 has 2 divisors, whose sum is σ = 4042121212908. Its totient is φ = 4042121212906.
The previous prime is 4042121212897. The next prime is 4042121212957. The reversal of 4042121212907 is 7092121212404.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4042121212907 - 214 = 4042121196523 is a prime.
It is not a weakly prime, because it can be changed into another prime (4042121212957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021060606453 + 2021060606454.
It is an arithmetic number, because the mean of its divisors is an integer number (2021060606454).
Almost surely, 24042121212907 is an apocalyptic number.
4042121212907 is a deficient number, since it is larger than the sum of its proper divisors (1).
4042121212907 is an equidigital number, since it uses as much as digits as its factorization.
4042121212907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 35.
The spelling of 4042121212907 in words is "four trillion, forty-two billion, one hundred twenty-one million, two hundred twelve thousand, nine hundred seven".
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