Base | Representation |
---|---|
bin | 111010110100100001001… |
… | …111111001101110110101 |
3 | 112022102102102202011012122 |
4 | 322310201033321232311 |
5 | 1012211231220323133 |
6 | 12332531503325325 |
7 | 565014360314126 |
oct | 72644117715665 |
9 | 15272372664178 |
10 | 4042122042293 |
11 | 1319288573475 |
12 | 5534825b0845 |
13 | 23422a6b5a0a |
14 | dd8d569404d |
15 | 70228e10498 |
hex | 3ad213f9bb5 |
4042122042293 has 2 divisors, whose sum is σ = 4042122042294. Its totient is φ = 4042122042292.
The previous prime is 4042122042181. The next prime is 4042122042307. The reversal of 4042122042293 is 3922402212404.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3368865689809 + 673256352484 = 1835447^2 + 820522^2 .
It is a cyclic number.
It is not a de Polignac number, because 4042122042293 - 220 = 4042120993717 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4042122044293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021061021146 + 2021061021147.
It is an arithmetic number, because the mean of its divisors is an integer number (2021061021147).
Almost surely, 24042122042293 is an apocalyptic number.
It is an amenable number.
4042122042293 is a deficient number, since it is larger than the sum of its proper divisors (1).
4042122042293 is an equidigital number, since it uses as much as digits as its factorization.
4042122042293 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 4042122042293 its reverse (3922402212404), we get a palindrome (7964524254697).
The spelling of 4042122042293 in words is "four trillion, forty-two billion, one hundred twenty-two million, forty-two thousand, two hundred ninety-three".
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