Base | Representation |
---|---|
bin | 111010110100100001010… |
… | …000001000110101000101 |
3 | 112022102102102212022001000 |
4 | 322310201100020311011 |
5 | 1012211231224313013 |
6 | 12332531504523513 |
7 | 565014360662331 |
oct | 72644120106505 |
9 | 15272372768030 |
10 | 4042122104133 |
11 | 1319288605983 |
12 | 553482620599 |
13 | 23422a707bc9 |
14 | dd8d56ac7c1 |
15 | 70228e23973 |
hex | 3ad21408d45 |
4042122104133 has 32 divisors (see below), whose sum is σ = 6128058499200. Its totient is φ = 2631879347328.
The previous prime is 4042122104131. The next prime is 4042122104149. The reversal of 4042122104133 is 3314012212404.
4042122104133 is a `hidden beast` number, since 4 + 0 + 4 + 21 + 221 + 0 + 413 + 3 = 666.
It is not a de Polignac number, because 4042122104133 - 21 = 4042122104131 is a prime.
It is a super-2 number, since 2×40421221041332 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 4042122104097 and 4042122104106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4042122104131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15985753 + ... + 16236641.
It is an arithmetic number, because the mean of its divisors is an integer number (191501828100).
Almost surely, 24042122104133 is an apocalyptic number.
4042122104133 is a gapful number since it is divisible by the number (43) formed by its first and last digit.
It is an amenable number.
4042122104133 is a deficient number, since it is larger than the sum of its proper divisors (2085936395067).
4042122104133 is a wasteful number, since it uses less digits than its factorization.
4042122104133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 264818 (or 264812 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 4042122104133 its reverse (3314012212404), we get a palindrome (7356134316537).
The spelling of 4042122104133 in words is "four trillion, forty-two billion, one hundred twenty-two million, one hundred four thousand, one hundred thirty-three".
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