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4042124011141 is a prime number
BaseRepresentation
bin111010110100100001010…
…111011010011010000101
3112022102102120110011221221
4322310201113122122011
51012211232221324031
612332532013440341
7565014413124166
oct72644127323205
915272376404857
104042124011141
111319289698717
125534831a00b1
1323422ac24c08
14dd8d5a4776d
157022919da11
hex3ad215da685

4042124011141 has 2 divisors, whose sum is σ = 4042124011142. Its totient is φ = 4042124011140.

The previous prime is 4042124011127. The next prime is 4042124011193. The reversal of 4042124011141 is 1411104212404.

4042124011141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3711194190916 + 330929820225 = 1926446^2 + 575265^2 .

It is a cyclic number.

It is not a de Polignac number, because 4042124011141 - 231 = 4039976527493 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4042124911141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021062005570 + 2021062005571.

It is an arithmetic number, because the mean of its divisors is an integer number (2021062005571).

Almost surely, 24042124011141 is an apocalyptic number.

It is an amenable number.

4042124011141 is a deficient number, since it is larger than the sum of its proper divisors (1).

4042124011141 is an equidigital number, since it uses as much as digits as its factorization.

4042124011141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1024, while the sum is 25.

Adding to 4042124011141 its reverse (1411104212404), we get a palindrome (5453228223545).

The spelling of 4042124011141 in words is "four trillion, forty-two billion, one hundred twenty-four million, eleven thousand, one hundred forty-one".