Base | Representation |
---|---|
bin | 111010110100110011001… |
… | …100011001000101110011 |
3 | 112022110012102021002021102 |
4 | 322310303030121011303 |
5 | 1012212340304041201 |
6 | 12333021420315015 |
7 | 565025004340412 |
oct | 72646314310563 |
9 | 15273172232242 |
10 | 4042423112051 |
11 | 1319422508655 |
12 | 5535473a2a6b |
13 | 234277b996bc |
14 | dd923665479 |
15 | 7024558126b |
hex | 3ad33319173 |
4042423112051 has 2 divisors, whose sum is σ = 4042423112052. Its totient is φ = 4042423112050.
The previous prime is 4042423112047. The next prime is 4042423112087. The reversal of 4042423112051 is 1502113242404.
It is a happy number.
4042423112051 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4042423112051 - 22 = 4042423112047 is a prime.
It is not a weakly prime, because it can be changed into another prime (4042423112851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021211556025 + 2021211556026.
It is an arithmetic number, because the mean of its divisors is an integer number (2021211556026).
Almost surely, 24042423112051 is an apocalyptic number.
4042423112051 is a deficient number, since it is larger than the sum of its proper divisors (1).
4042423112051 is an equidigital number, since it uses as much as digits as its factorization.
4042423112051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 29.
Adding to 4042423112051 its reverse (1502113242404), we get a palindrome (5544536354455).
The spelling of 4042423112051 in words is "four trillion, forty-two billion, four hundred twenty-three million, one hundred twelve thousand, fifty-one".
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