Base | Representation |
---|---|
bin | 111010110100110011100… |
… | …111000110001000110011 |
3 | 112022110012220102201211011 |
4 | 322310303213012020303 |
5 | 1012212344102043212 |
6 | 12333022230331351 |
7 | 565025121004336 |
oct | 72646347061063 |
9 | 15273186381734 |
10 | 4042430112307 |
11 | 1319426459a94 |
12 | 5535497b9b57 |
13 | 23427947aa72 |
14 | dd92456861d |
15 | 70245eb54a7 |
hex | 3ad339c6233 |
4042430112307 has 2 divisors, whose sum is σ = 4042430112308. Its totient is φ = 4042430112306.
The previous prime is 4042430112209. The next prime is 4042430112349. The reversal of 4042430112307 is 7032110342404.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4042430112307 - 215 = 4042430079539 is a prime.
It is not a weakly prime, because it can be changed into another prime (4042430112367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021215056153 + 2021215056154.
It is an arithmetic number, because the mean of its divisors is an integer number (2021215056154).
Almost surely, 24042430112307 is an apocalyptic number.
4042430112307 is a deficient number, since it is larger than the sum of its proper divisors (1).
4042430112307 is an equidigital number, since it uses as much as digits as its factorization.
4042430112307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 31.
The spelling of 4042430112307 in words is "four trillion, forty-two billion, four hundred thirty million, one hundred twelve thousand, three hundred seven".
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