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4042513551 = 329371255829
BaseRepresentation
bin1111000011110011…
…1101110010001111
3101102201200222002010
43300330331302033
531234340413201
61505045032303
7202114540536
oct36074756217
911381628063
104042513551
11179499129a
129499b5693
134c568836b
142a4c5d31d
15189d71bd6
hexf0f3dc8f

4042513551 has 16 divisors (see below), whose sum is σ = 5726584800. Its totient is φ = 2531749248.

The previous prime is 4042513543. The next prime is 4042513567. The reversal of 4042513551 is 1553152404.

It is not a de Polignac number, because 4042513551 - 23 = 4042513543 is a prime.

It is a super-3 number, since 3×40425135513 (a number of 30 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4042513571) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 624696 + ... + 631133.

It is an arithmetic number, because the mean of its divisors is an integer number (357911550).

Almost surely, 24042513551 is an apocalyptic number.

4042513551 is a deficient number, since it is larger than the sum of its proper divisors (1684071249).

4042513551 is a wasteful number, since it uses less digits than its factorization.

4042513551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1255898.

The product of its (nonzero) digits is 12000, while the sum is 30.

The square root of 4042513551 is about 63580.7640013865. The cubic root of 4042513551 is about 1593.0050826410.

Adding to 4042513551 its reverse (1553152404), we get a palindrome (5595665955).

The spelling of 4042513551 in words is "four billion, forty-two million, five hundred thirteen thousand, five hundred fifty-one".

Divisors: 1 3 29 37 87 111 1073 3219 1255829 3767487 36419041 46465673 109257123 139397019 1347504517 4042513551