Base | Representation |
---|---|
bin | 1011110001000101101… |
… | …01010000101111111001 |
3 | 1102122121011001210010221 |
4 | 11320202311100233321 |
5 | 23111012144012101 |
6 | 505423230340041 |
7 | 41132132313562 |
oct | 5704265205771 |
9 | 1378534053127 |
10 | 404311313401 |
11 | 146516217a26 |
12 | 6643705a621 |
13 | 2c1848bc168 |
14 | 157d69d3169 |
15 | a7b5164aa1 |
hex | 5e22d50bf9 |
404311313401 has 4 divisors (see below), whose sum is σ = 404312594832. Its totient is φ = 404310031972.
The previous prime is 404311313381. The next prime is 404311313477. The reversal of 404311313401 is 104313113404.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 404311313401 - 217 = 404311182329 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (404311313491) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202206 + ... + 921688.
It is an arithmetic number, because the mean of its divisors is an integer number (101078148708).
Almost surely, 2404311313401 is an apocalyptic number.
It is an amenable number.
404311313401 is a deficient number, since it is larger than the sum of its proper divisors (1281431).
404311313401 is an equidigital number, since it uses as much as digits as its factorization.
404311313401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1281430.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 404311313401 its reverse (104313113404), we get a palindrome (508624426805).
The spelling of 404311313401 in words is "four hundred four billion, three hundred eleven million, three hundred thirteen thousand, four hundred one".
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