Base | Representation |
---|---|
bin | 111010110101011100010… |
… | …101010010011100100011 |
3 | 112022111222111222202211221 |
4 | 322311130111102130203 |
5 | 1012220244001404422 |
6 | 12333214113515511 |
7 | 565051055045323 |
oct | 72653425223443 |
9 | 15274874882757 |
10 | 4043113309987 |
11 | 1319747072574 |
12 | 5536ba572b97 |
13 | 234357b8634b |
14 | dd98b1ab283 |
15 | 70285e693c7 |
hex | 3ad5c552723 |
4043113309987 has 2 divisors, whose sum is σ = 4043113309988. Its totient is φ = 4043113309986.
The previous prime is 4043113309979. The next prime is 4043113310039. The reversal of 4043113309987 is 7899033113404.
It is an a-pointer prime, because the next prime (4043113310039) can be obtained adding 4043113309987 to its sum of digits (52).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4043113309987 - 23 = 4043113309979 is a prime.
It is not a weakly prime, because it can be changed into another prime (4043113309787) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021556654993 + 2021556654994.
It is an arithmetic number, because the mean of its divisors is an integer number (2021556654994).
Almost surely, 24043113309987 is an apocalyptic number.
4043113309987 is a deficient number, since it is larger than the sum of its proper divisors (1).
4043113309987 is an equidigital number, since it uses as much as digits as its factorization.
4043113309987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1959552, while the sum is 52.
The spelling of 4043113309987 in words is "four trillion, forty-three billion, one hundred thirteen million, three hundred nine thousand, nine hundred eighty-seven".
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