Base | Representation |
---|---|
bin | 1011110001001001011… |
… | …11010101001011101011 |
3 | 1102122200101021112112010 |
4 | 11320210233111023223 |
5 | 23111043342010011 |
6 | 505430332251003 |
7 | 41133001311342 |
oct | 5704457251353 |
9 | 1378611245463 |
10 | 404343313131 |
11 | 14653229388a |
12 | 66445910a63 |
13 | 2c18b414404 |
14 | 157dad62b59 |
15 | a7b7d861a6 |
hex | 5e24bd52eb |
404343313131 has 4 divisors (see below), whose sum is σ = 539124417512. Its totient is φ = 269562208752.
The previous prime is 404343313091. The next prime is 404343313159. The reversal of 404343313131 is 131313343404.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 404343313131 - 29 = 404343312619 is a prime.
It is a super-2 number, since 2×4043433131312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (404343313831) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67390552186 + ... + 67390552191.
It is an arithmetic number, because the mean of its divisors is an integer number (134781104378).
Almost surely, 2404343313131 is an apocalyptic number.
404343313131 is a deficient number, since it is larger than the sum of its proper divisors (134781104381).
404343313131 is a wasteful number, since it uses less digits than its factorization.
404343313131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 134781104380.
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 404343313131 its reverse (131313343404), we get a palindrome (535656656535).
The spelling of 404343313131 in words is "four hundred four billion, three hundred forty-three million, three hundred thirteen thousand, one hundred thirty-one".
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