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40441123985617 is a prime number
BaseRepresentation
bin10010011000111111011101…
…10101000101100011010001
312022012010121110112022012201
421030133232311011203101
520300041410220014432
6222002221302123201
711342526516050365
oct1114375665054321
9168163543468181
1040441123985617
1111981a91212543
124651916720501
131974773ab65b4
149db50a22d2a5
154a1e76b1eee7
hex24c7eed458d1

40441123985617 has 2 divisors, whose sum is σ = 40441123985618. Its totient is φ = 40441123985616.

The previous prime is 40441123985579. The next prime is 40441123985657. The reversal of 40441123985617 is 71658932114404.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 35700732550081 + 4740391435536 = 5975009^2 + 2177244^2 .

It is a cyclic number.

It is not a de Polignac number, because 40441123985617 - 239 = 39891368171729 is a prime.

It is not a weakly prime, because it can be changed into another prime (40441123985657) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20220561992808 + 20220561992809.

It is an arithmetic number, because the mean of its divisors is an integer number (20220561992809).

It is a 1-persistent number, because it is pandigital, but 2⋅40441123985617 = 80882247971234 is not.

Almost surely, 240441123985617 is an apocalyptic number.

It is an amenable number.

40441123985617 is a deficient number, since it is larger than the sum of its proper divisors (1).

40441123985617 is an equidigital number, since it uses as much as digits as its factorization.

40441123985617 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5806080, while the sum is 55.

The spelling of 40441123985617 in words is "forty trillion, four hundred forty-one billion, one hundred twenty-three million, nine hundred eighty-five thousand, six hundred seventeen".