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40442112131 = 97141649961
BaseRepresentation
bin100101101010100010…
…011010100010000011
310212101110222011022212
4211222202122202003
51130311140042011
630325010452335
72631123165311
oct455242324203
9125343864285
1040442112131
1116173577473
127a07b940ab
133a76849b85
141d591b50b1
1510ba71808b
hex96a89a883

40442112131 has 4 divisors (see below), whose sum is σ = 40483763064. Its totient is φ = 40400461200.

The previous prime is 40442112121. The next prime is 40442112143. The reversal of 40442112131 is 13121124404.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40442112131 - 234 = 23262242947 is a prime.

It is a super-2 number, since 2×404421121312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 40442112097 and 40442112106.

It is not an unprimeable number, because it can be changed into a prime (40442112121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20824010 + ... + 20825951.

It is an arithmetic number, because the mean of its divisors is an integer number (10120940766).

Almost surely, 240442112131 is an apocalyptic number.

40442112131 is a deficient number, since it is larger than the sum of its proper divisors (41650933).

40442112131 is an equidigital number, since it uses as much as digits as its factorization.

40442112131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41650932.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 40442112131 its reverse (13121124404), we get a palindrome (53563236535).

The spelling of 40442112131 in words is "forty billion, four hundred forty-two million, one hundred twelve thousand, one hundred thirty-one".

Divisors: 1 971 41649961 40442112131