Base | Representation |
---|---|
bin | 10010011010001110101010… |
… | …00010101000000101110111 |
3 | 12022100012100112210102202122 |
4 | 21031013111002220011313 |
5 | 20301240444044002221 |
6 | 222033532233230155 |
7 | 11345563235523425 |
oct | 1115072502500567 |
9 | 168305315712678 |
10 | 40483641000311 |
11 | 11999019a35a13 |
12 | 465a00156235b |
13 | 197878b474962 |
14 | 9dd5c0bda115 |
15 | 4a3114593eab |
hex | 24d1d50a8177 |
40483641000311 has 2 divisors, whose sum is σ = 40483641000312. Its totient is φ = 40483641000310.
The previous prime is 40483641000293. The next prime is 40483641000371. The reversal of 40483641000311 is 11300014638404.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40483641000311 - 210 = 40483640999287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40483641000371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20241820500155 + 20241820500156.
It is an arithmetic number, because the mean of its divisors is an integer number (20241820500156).
Almost surely, 240483641000311 is an apocalyptic number.
40483641000311 is a deficient number, since it is larger than the sum of its proper divisors (1).
40483641000311 is an equidigital number, since it uses as much as digits as its factorization.
40483641000311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 35.
Adding to 40483641000311 its reverse (11300014638404), we get a palindrome (51783655638715).
The spelling of 40483641000311 in words is "forty trillion, four hundred eighty-three billion, six hundred forty-one million, three hundred eleven", and thus it is an aban number.
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