Base | Representation |
---|---|
bin | 111010111101000111010… |
… | …010010001010101110011 |
3 | 112100022020120000200120222 |
4 | 322331013102101111303 |
5 | 1012334131113211313 |
6 | 12341055313323255 |
7 | 565462142634032 |
oct | 72750722212563 |
9 | 15308216020528 |
10 | 4051350132083 |
11 | 1322193592961 |
12 | 555218b6652b |
13 | 23506b4a6987 |
14 | 10012d0c0719 |
15 | 705b9144208 |
hex | 3af47491573 |
4051350132083 has 2 divisors, whose sum is σ = 4051350132084. Its totient is φ = 4051350132082.
The previous prime is 4051350132001. The next prime is 4051350132131. The reversal of 4051350132083 is 3802310531504.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4051350132083 - 28 = 4051350131827 is a prime.
It is not a weakly prime, because it can be changed into another prime (4051350135083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2025675066041 + 2025675066042.
It is an arithmetic number, because the mean of its divisors is an integer number (2025675066042).
Almost surely, 24051350132083 is an apocalyptic number.
4051350132083 is a deficient number, since it is larger than the sum of its proper divisors (1).
4051350132083 is an equidigital number, since it uses as much as digits as its factorization.
4051350132083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 4051350132083 its reverse (3802310531504), we get a palindrome (7853660663587).
The spelling of 4051350132083 in words is "four trillion, fifty-one billion, three hundred fifty million, one hundred thirty-two thousand, eighty-three".
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