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4052410442011 = 7951296334709
BaseRepresentation
bin111010111110000110011…
…111000010000100011011
3112100101222110012000101001
4322332012133002010123
51012343314033121021
612341352431405431
7565530336262441
oct72760637020433
915311873160331
104052410442011
111322688059458
12555474083877
132351aa06bbb9
141001cdc4ab91
157062c28a091
hex3af867c211b

4052410442011 has 4 divisors (see below), whose sum is σ = 4103706776800. Its totient is φ = 4001114107224.

The previous prime is 4052410441979. The next prime is 4052410442021. The reversal of 4052410442011 is 1102440142504.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4052410442011 - 25 = 4052410441979 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4052410442021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25648167276 + ... + 25648167433.

It is an arithmetic number, because the mean of its divisors is an integer number (1025926694200).

Almost surely, 24052410442011 is an apocalyptic number.

4052410442011 is a deficient number, since it is larger than the sum of its proper divisors (51296334789).

4052410442011 is an equidigital number, since it uses as much as digits as its factorization.

4052410442011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51296334788.

The product of its (nonzero) digits is 5120, while the sum is 28.

Adding to 4052410442011 its reverse (1102440142504), we get a palindrome (5154850584515).

The spelling of 4052410442011 in words is "four trillion, fifty-two billion, four hundred ten million, four hundred forty-two thousand, eleven".

Divisors: 1 79 51296334709 4052410442011