Base | Representation |
---|---|
bin | 111010111111101100100… |
… | …001011100011000100001 |
3 | 112100120101202102221210211 |
4 | 322333230201130120201 |
5 | 1012410320310200423 |
6 | 12342234343454121 |
7 | 565620634252243 |
oct | 72775441343041 |
9 | 15316352387724 |
10 | 4054122350113 |
11 | 1323386415340 |
12 | 555871457341 |
13 | 2353c0927684 |
14 | 100313352093 |
15 | 706cc6e210d |
hex | 3afec85c621 |
4054122350113 has 24 divisors (see below), whose sum is σ = 4512384553248. Its totient is φ = 3612235536000.
The previous prime is 4054122350111. The next prime is 4054122350129. The reversal of 4054122350113 is 3110532214504.
It is not a de Polignac number, because 4054122350113 - 21 = 4054122350111 is a prime.
It is a super-2 number, since 2×40541223501132 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4054122350111) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 11325370 + ... + 11677852.
It is an arithmetic number, because the mean of its divisors is an integer number (188016023052).
Almost surely, 24054122350113 is an apocalyptic number.
It is an amenable number.
4054122350113 is a deficient number, since it is larger than the sum of its proper divisors (458262203135).
4054122350113 is a wasteful number, since it uses less digits than its factorization.
4054122350113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 352897 (or 352836 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 4054122350113 its reverse (3110532214504), we get a palindrome (7164654564617).
The spelling of 4054122350113 in words is "four trillion, fifty-four billion, one hundred twenty-two million, three hundred fifty thousand, one hundred thirteen".
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