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405501013313 = 1136863728483
BaseRepresentation
bin1011110011010011011…
…11100110110101000001
31102202200001200210121122
411321221233212311001
523120431224411223
6510141250002025
741203456512464
oct5715157466501
91382601623548
10405501013313
11146a768290a0
1266709576315
132c3142182c6
14158aaa012db
15a8348185c8
hex5e69be6d41

405501013313 has 4 divisors (see below), whose sum is σ = 442364741808. Its totient is φ = 368637284820.

The previous prime is 405501013279. The next prime is 405501013349. The reversal of 405501013313 is 313310105504.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 405501013313 - 218 = 405500751169 is a prime.

It is not an unprimeable number, because it can be changed into a prime (405501013363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18431864231 + ... + 18431864252.

It is an arithmetic number, because the mean of its divisors is an integer number (110591185452).

Almost surely, 2405501013313 is an apocalyptic number.

It is an amenable number.

405501013313 is a deficient number, since it is larger than the sum of its proper divisors (36863728495).

405501013313 is a wasteful number, since it uses less digits than its factorization.

405501013313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36863728494.

The product of its (nonzero) digits is 2700, while the sum is 26.

Adding to 405501013313 its reverse (313310105504), we get a palindrome (718811118817).

The spelling of 405501013313 in words is "four hundred five billion, five hundred one million, thirteen thousand, three hundred thirteen".

Divisors: 1 11 36863728483 405501013313