Base | Representation |
---|---|
bin | 111011000001000001010… |
… | …010010110000101001001 |
3 | 112100201001212101101122121 |
4 | 323001001102112011021 |
5 | 1012421223340033442 |
6 | 12343031424251241 |
7 | 566001113043133 |
oct | 73010122260511 |
9 | 15321055341577 |
10 | 4055544455497 |
11 | 1323a46132147 |
12 | 555ba9770b21 |
13 | 235589445952 |
14 | 10040a17a053 |
15 | 707624a1967 |
hex | 3b041496149 |
4055544455497 has 2 divisors, whose sum is σ = 4055544455498. Its totient is φ = 4055544455496.
The previous prime is 4055544455489. The next prime is 4055544455513. The reversal of 4055544455497 is 7945544455504.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3952239424576 + 103305030921 = 1988024^2 + 321411^2 .
It is a cyclic number.
It is not a de Polignac number, because 4055544455497 - 23 = 4055544455489 is a prime.
It is not a weakly prime, because it can be changed into another prime (4055544455407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2027772227748 + 2027772227749.
It is an arithmetic number, because the mean of its divisors is an integer number (2027772227749).
Almost surely, 24055544455497 is an apocalyptic number.
It is an amenable number.
4055544455497 is a deficient number, since it is larger than the sum of its proper divisors (1).
4055544455497 is an equidigital number, since it uses as much as digits as its factorization.
4055544455497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 201600000, while the sum is 61.
The spelling of 4055544455497 in words is "four trillion, fifty-five billion, five hundred forty-four million, four hundred fifty-five thousand, four hundred ninety-seven".
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