4055544455513 has 2 divisors, whose sum is σ = 4055544455514. Its totient is φ = 4055544455512.

The previous prime is 4055544455497. The next prime is 4055544455527. The reversal of 4055544455513 is 3155544455504.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3808929915904 + 246614539609 = 1951648^2 + 496603^2 .

It is a cyclic number.

It is not a de Polignac number, because 4055544455513 - 2⁴ = 4055544455497 is a prime.

It is not a weakly prime, because it can be changed into another prime (4055544454513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2027772227756 + 2027772227757.

It is an arithmetic number, because the mean of its divisors is an integer number (2027772227757).

Almost surely, 2^{4055544455513} is an apocalyptic number.

It is an amenable number.

4055544455513 is a deficient number, since it is larger than the sum of its proper divisors (1).

4055544455513 is an equidigital number, since it uses as much as digits as its factorization.

4055544455513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12000000, while the sum is 50.

Subtracting from 4055544455513 its reverse (3155544455504), we obtain a palindrome (900000000009).

The spelling of 4055544455513 in words is "four trillion, fifty-five billion, five hundred forty-four million, four hundred fifty-five thousand, five hundred thirteen".