Base | Representation |
---|---|
bin | 111011000001110100011… |
… | …011001001001010101001 |
3 | 112100210021122202111010201 |
4 | 323001310123021022221 |
5 | 1012430003003244123 |
6 | 12343252513112201 |
7 | 566031301332613 |
oct | 73016433111251 |
9 | 15323248674121 |
10 | 4056402399913 |
11 | 132434644a516 |
12 | 5561a8b58661 |
13 | 235695105c76 |
14 | 10048c0a9db3 |
15 | 707b29725ad |
hex | 3b0746c92a9 |
4056402399913 has 2 divisors, whose sum is σ = 4056402399914. Its totient is φ = 4056402399912.
The previous prime is 4056402399911. The next prime is 4056402400007. The reversal of 4056402399913 is 3199932046504.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3305316710809 + 751085689104 = 1818053^2 + 866652^2 .
It is a cyclic number.
It is not a de Polignac number, because 4056402399913 - 21 = 4056402399911 is a prime.
Together with 4056402399911, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (4056402399911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2028201199956 + 2028201199957.
It is an arithmetic number, because the mean of its divisors is an integer number (2028201199957).
Almost surely, 24056402399913 is an apocalyptic number.
It is an amenable number.
4056402399913 is a deficient number, since it is larger than the sum of its proper divisors (1).
4056402399913 is an equidigital number, since it uses as much as digits as its factorization.
4056402399913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6298560, while the sum is 55.
The spelling of 4056402399913 in words is "four trillion, fifty-six billion, four hundred two million, three hundred ninety-nine thousand, nine hundred thirteen".
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