Base | Representation |
---|---|
bin | 111011000111011010100… |
… | …101011000001001011100 |
3 | 112101100210102121120011101 |
4 | 323013122211120021130 |
5 | 1013024304244413134 |
6 | 12350125045202444 |
7 | 566333224345651 |
oct | 73073245301134 |
9 | 15340712546141 |
10 | 4062411326044 |
11 | 132694a317675 |
12 | 5573a5400424 |
13 | 236111ca8866 |
14 | 10089c15dc28 |
15 | 70a1526ee14 |
hex | 3b1da95825c |
4062411326044 has 6 divisors (see below), whose sum is σ = 7109219820584. Its totient is φ = 2031205663020.
The previous prime is 4062411326041. The next prime is 4062411326053. The reversal of 4062411326044 is 4406231142604.
4062411326044 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 4062411325994 and 4062411326012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4062411326041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507801415752 + ... + 507801415759.
Almost surely, 24062411326044 is an apocalyptic number.
It is an amenable number.
4062411326044 is a deficient number, since it is larger than the sum of its proper divisors (3046808494540).
4062411326044 is a wasteful number, since it uses less digits than its factorization.
4062411326044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1015602831515 (or 1015602831513 counting only the distinct ones).
The product of its (nonzero) digits is 110592, while the sum is 37.
Adding to 4062411326044 its reverse (4406231142604), we get a palindrome (8468642468648).
The spelling of 4062411326044 in words is "four trillion, sixty-two billion, four hundred eleven million, three hundred twenty-six thousand, forty-four".
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