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40653523471189 is a prime number
BaseRepresentation
bin10010011111001011000101…
…10100110100101101010101
312022221102211221122010020111
421033211202310310231111
520312031404002034224
6222243545412203021
711364056131641166
oct1117454264645525
9168842757563214
1040653523471189
1111a54076189782
124686b12909471
13198b7c2c5b685
14a078d8ddb76d
154a7758925d94
hex24f962d34b55

40653523471189 has 2 divisors, whose sum is σ = 40653523471190. Its totient is φ = 40653523471188.

The previous prime is 40653523471129. The next prime is 40653523471213. The reversal of 40653523471189 is 98117432535604.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 34170220980900 + 6483302490289 = 5845530^2 + 2546233^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40653523471189 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40653523471129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20326761735594 + 20326761735595.

It is an arithmetic number, because the mean of its divisors is an integer number (20326761735595).

It is a 1-persistent number, because it is pandigital, but 2⋅40653523471189 = 81307046942378 is not.

Almost surely, 240653523471189 is an apocalyptic number.

It is an amenable number.

40653523471189 is a deficient number, since it is larger than the sum of its proper divisors (1).

40653523471189 is an equidigital number, since it uses as much as digits as its factorization.

40653523471189 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21772800, while the sum is 58.

The spelling of 40653523471189 in words is "forty trillion, six hundred fifty-three billion, five hundred twenty-three million, four hundred seventy-one thousand, one hundred eighty-nine".