Base | Representation |
---|---|
bin | 100101111000001100… |
… | …010000111111000011 |
3 | 10212222110000100210221 |
4 | 211320030100333003 |
5 | 1131243310440013 |
6 | 30403432403511 |
7 | 2636604245605 |
oct | 457014207703 |
9 | 125873010727 |
10 | 40671186883 |
11 | 16280908748 |
12 | 7a70846597 |
13 | 3ab2143c72 |
14 | 1d7b7a5175 |
15 | 10d08b708d |
hex | 978310fc3 |
40671186883 has 2 divisors, whose sum is σ = 40671186884. Its totient is φ = 40671186882.
The previous prime is 40671186863. The next prime is 40671186889. The reversal of 40671186883 is 38868117604.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40671186883 - 29 = 40671186371 is a prime.
It is a super-2 number, since 2×406711868832 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 40671186883.
It is not a weakly prime, because it can be changed into another prime (40671186889) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20335593441 + 20335593442.
It is an arithmetic number, because the mean of its divisors is an integer number (20335593442).
Almost surely, 240671186883 is an apocalyptic number.
40671186883 is a deficient number, since it is larger than the sum of its proper divisors (1).
40671186883 is an equidigital number, since it uses as much as digits as its factorization.
40671186883 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1548288, while the sum is 52.
The spelling of 40671186883 in words is "forty billion, six hundred seventy-one million, one hundred eighty-six thousand, eight hundred eighty-three".
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