Base | Representation |
---|---|
bin | 111011001110100110001… |
… | …111100100000000010111 |
3 | 112102002200212201122000212 |
4 | 323032212033210000113 |
5 | 1013141103010024212 |
6 | 12353442212000035 |
7 | 600025305516053 |
oct | 73164617440027 |
9 | 15362625648025 |
10 | 4070123126807 |
11 | 132a147440731 |
12 | 55899800001b |
13 | 236a708c328a |
14 | 100dd0446c63 |
15 | 70d172dce22 |
hex | 3b3a63e4017 |
4070123126807 has 2 divisors, whose sum is σ = 4070123126808. Its totient is φ = 4070123126806.
The previous prime is 4070123126777. The next prime is 4070123126851. The reversal of 4070123126807 is 7086213210704.
4070123126807 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4070123126807 - 214 = 4070123110423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4070123126107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2035061563403 + 2035061563404.
It is an arithmetic number, because the mean of its divisors is an integer number (2035061563404).
Almost surely, 24070123126807 is an apocalyptic number.
4070123126807 is a deficient number, since it is larger than the sum of its proper divisors (1).
4070123126807 is an equidigital number, since it uses as much as digits as its factorization.
4070123126807 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112896, while the sum is 41.
The spelling of 4070123126807 in words is "four trillion, seventy billion, one hundred twenty-three million, one hundred twenty-six thousand, eight hundred seven".
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