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4075568813341 is a prime number
BaseRepresentation
bin111011010011101010110…
…101001101010100011101
3112102121202101202011120201
4323103222311031110131
51013233231104011331
612400142423543501
7600310252216144
oct73235265152435
915377671664521
104075568813341
111331491388613
12559a578bab91
1323742ab9b3bc
141013897a275b
157103542ea61
hex3b4ead4d51d

4075568813341 has 2 divisors, whose sum is σ = 4075568813342. Its totient is φ = 4075568813340.

The previous prime is 4075568813333. The next prime is 4075568813399. The reversal of 4075568813341 is 1433188655704.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2540995402500 + 1534573410841 = 1594050^2 + 1238779^2 .

It is a cyclic number.

It is not a de Polignac number, because 4075568813341 - 23 = 4075568813333 is a prime.

It is a super-2 number, since 2×40755688133412 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4075568213341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2037784406670 + 2037784406671.

It is an arithmetic number, because the mean of its divisors is an integer number (2037784406671).

Almost surely, 24075568813341 is an apocalyptic number.

It is an amenable number.

4075568813341 is a deficient number, since it is larger than the sum of its proper divisors (1).

4075568813341 is an equidigital number, since it uses as much as digits as its factorization.

4075568813341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9676800, while the sum is 55.

The spelling of 4075568813341 in words is "four trillion, seventy-five billion, five hundred sixty-eight million, eight hundred thirteen thousand, three hundred forty-one".