Base | Representation |
---|---|
bin | 10010100010101101011011… |
… | …01010100000101101110111 |
3 | 12100101001111111221001022220 |
4 | 21101112231222200231313 |
5 | 20321024234231041401 |
6 | 222415443253253423 |
7 | 11405620312420341 |
oct | 1121265552405567 |
9 | 170331444831286 |
10 | 40775038143351 |
11 | 11aa0662035476 |
12 | 46a6585934273 |
13 | 199a0b9ba4355 |
14 | a0d745586291 |
15 | 4aa9bb873336 |
hex | 2515adaa0b77 |
40775038143351 has 4 divisors (see below), whose sum is σ = 54366717524472. Its totient is φ = 27183358762232.
The previous prime is 40775038143241. The next prime is 40775038143383. The reversal of 40775038143351 is 15334183057704.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 40775038143351 - 211 = 40775038141303 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 40775038143294 and 40775038143303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (40775038143391) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6795839690556 + ... + 6795839690561.
It is an arithmetic number, because the mean of its divisors is an integer number (13591679381118).
Almost surely, 240775038143351 is an apocalyptic number.
40775038143351 is a deficient number, since it is larger than the sum of its proper divisors (13591679381121).
40775038143351 is a wasteful number, since it uses less digits than its factorization.
40775038143351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13591679381120.
The product of its (nonzero) digits is 4233600, while the sum is 51.
The spelling of 40775038143351 in words is "forty trillion, seven hundred seventy-five billion, thirty-eight million, one hundred forty-three thousand, three hundred fifty-one".
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