Base | Representation |
---|---|
bin | 111011011000000111001… |
… | …111011001111100010011 |
3 | 112110002001221100101211202 |
4 | 323120013033121330103 |
5 | 1013323014121111011 |
6 | 12402252115501415 |
7 | 600536432141066 |
oct | 73300717317423 |
9 | 15402057311752 |
10 | 4080340410131 |
11 | 133350a872937 |
12 | 55a9698b786b |
13 | 237a0b60975b |
14 | 1016bd3aa8dd |
15 | 712142bb23b |
hex | 3b6073d9f13 |
4080340410131 has 2 divisors, whose sum is σ = 4080340410132. Its totient is φ = 4080340410130.
The previous prime is 4080340410127. The next prime is 4080340410143. The reversal of 4080340410131 is 1310140430804.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4080340410131 - 22 = 4080340410127 is a prime.
It is a super-2 number, since 2×40803404101312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4080340410094 and 4080340410103.
It is not a weakly prime, because it can be changed into another prime (4080340410121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2040170205065 + 2040170205066.
It is an arithmetic number, because the mean of its divisors is an integer number (2040170205066).
Almost surely, 24080340410131 is an apocalyptic number.
4080340410131 is a deficient number, since it is larger than the sum of its proper divisors (1).
4080340410131 is an equidigital number, since it uses as much as digits as its factorization.
4080340410131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 4080340410131 its reverse (1310140430804), we get a palindrome (5390480840935).
The spelling of 4080340410131 in words is "four trillion, eighty billion, three hundred forty million, four hundred ten thousand, one hundred thirty-one".
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