Base | Representation |
---|---|
bin | 111011101010100001001… |
… | …000010110001001000011 |
3 | 112111222002011111021111012 |
4 | 323222201020112021003 |
5 | 1014134002120320003 |
6 | 12415321053511135 |
7 | 602136231663431 |
oct | 73524110261103 |
9 | 15458064437435 |
10 | 4100102120003 |
11 | 1340930836a6a |
12 | 562763aa24ab |
13 | 23983a8118c6 |
14 | 102635b83d51 |
15 | 719be1678d8 |
hex | 3baa1216243 |
4100102120003 has 2 divisors, whose sum is σ = 4100102120004. Its totient is φ = 4100102120002.
The previous prime is 4100102119987. The next prime is 4100102120017. The reversal of 4100102120003 is 3000212010014.
It is an a-pointer prime, because the next prime (4100102120017) can be obtained adding 4100102120003 to its sum of digits (14).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4100102120003 - 24 = 4100102119987 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4100102120003.
It is not a weakly prime, because it can be changed into another prime (4100102120063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2050051060001 + 2050051060002.
It is an arithmetic number, because the mean of its divisors is an integer number (2050051060002).
Almost surely, 24100102120003 is an apocalyptic number.
4100102120003 is a deficient number, since it is larger than the sum of its proper divisors (1).
4100102120003 is an equidigital number, since it uses as much as digits as its factorization.
4100102120003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 4100102120003 its reverse (3000212010014), we get a palindrome (7100314130017).
The spelling of 4100102120003 in words is "four trillion, one hundred billion, one hundred two million, one hundred twenty thousand, three".
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