41001131 has 2 divisors, whose sum is σ = 41001132. Its totient is φ = 41001130.

The previous prime is 41001109. The next prime is 41001139. The reversal of 41001131 is 13110014.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 41001131 - 2⁶ = 41001067 is a prime.

It is a super-2 number, since 2×41001131² = 3362185486558322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (41001139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20500565 + 20500566.

It is an arithmetic number, because the mean of its divisors is an integer number (20500566).

Almost surely, 2^41001131 is an apocalyptic number.

41001131 is a deficient number, since it is larger than the sum of its proper divisors (1).

41001131 is an equidigital number, since it uses as much as digits as its factorization.

41001131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 41001131 is about 6403.2125530861. The cubic root of 41001131 is about 344.8248946869.

Adding to 41001131 its reverse (13110014), we get a palindrome (54111145).

The spelling of 41001131 in words is "forty-one million, one thousand, one hundred thirty-one".