Base | Representation |
---|---|
bin | 100110001011111111… |
… | …101011010101001001 |
3 | 10220211121012010101112 |
4 | 212023333223111021 |
5 | 1132433334244431 |
6 | 30500421500105 |
7 | 2651050262213 |
oct | 461377532511 |
9 | 126747163345 |
10 | 41003431241 |
11 | 16431405863 |
12 | 7b43b71635 |
13 | 3b35c21466 |
14 | 1dad96d5b3 |
15 | 10eeb44c2b |
hex | 98bfeb549 |
41003431241 has 4 divisors (see below), whose sum is σ = 41015060352. Its totient is φ = 40991802132.
The previous prime is 41003431229. The next prime is 41003431253. The reversal of 41003431241 is 14213430014.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (41003431229) and next prime (41003431253).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41003431241 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (41003431211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5809265 + ... + 5816318.
It is an arithmetic number, because the mean of its divisors is an integer number (10253765088).
Almost surely, 241003431241 is an apocalyptic number.
It is an amenable number.
41003431241 is a deficient number, since it is larger than the sum of its proper divisors (11629111).
41003431241 is a wasteful number, since it uses less digits than its factorization.
41003431241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11629110.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 41003431241 its reverse (14213430014), we get a palindrome (55216861255).
The spelling of 41003431241 in words is "forty-one billion, three million, four hundred thirty-one thousand, two hundred forty-one".
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