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410104113 = 3197194809
BaseRepresentation
bin11000011100011…
…011000100110001
31001120200110002020
4120130123010301
51314441312423
6104405542053
713106553546
oct3034330461
91046613066
10410104113
111a0547321
12b5414929
1366c6b673
143c674bcd
152600c4e3
hex1871b131

410104113 has 8 divisors (see below), whose sum is σ = 575584800. Its totient is φ = 259013088.

The previous prime is 410104091. The next prime is 410104133. The reversal of 410104113 is 311401014.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 410104113 - 25 = 410104081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 410104092 and 410104101.

It is not an unprimeable number, because it can be changed into a prime (410104133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3597348 + ... + 3597461.

It is an arithmetic number, because the mean of its divisors is an integer number (71948100).

Almost surely, 2410104113 is an apocalyptic number.

It is an amenable number.

410104113 is a deficient number, since it is larger than the sum of its proper divisors (165480687).

410104113 is a wasteful number, since it uses less digits than its factorization.

410104113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7194831.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 410104113 is about 20251.0274554157. The cubic root of 410104113 is about 742.9587610335.

Adding to 410104113 its reverse (311401014), we get a palindrome (721505127).

The spelling of 410104113 in words is "four hundred ten million, one hundred four thousand, one hundred thirteen".

Divisors: 1 3 19 57 7194809 21584427 136701371 410104113