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41024341153 is a prime number
BaseRepresentation
bin100110001101001111…
…011100010010100001
310220220001112110101201
4212031033130102201
51133004212404103
630502450001201
72651423101105
oct461517342241
9126801473351
1041024341153
1116442197784
127b4ab76201
133b3a362aa3
141db2653905
1511018c551d
hex98d3dc4a1

41024341153 has 2 divisors, whose sum is σ = 41024341154. Its totient is φ = 41024341152.

The previous prime is 41024341147. The next prime is 41024341177. The reversal of 41024341153 is 35114342014.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21730297744 + 19294043409 = 147412^2 + 138903^2 .

It is a cyclic number.

It is not a de Polignac number, because 41024341153 - 221 = 41022244001 is a prime.

It is not a weakly prime, because it can be changed into another prime (41024341123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20512170576 + 20512170577.

It is an arithmetic number, because the mean of its divisors is an integer number (20512170577).

Almost surely, 241024341153 is an apocalyptic number.

It is an amenable number.

41024341153 is a deficient number, since it is larger than the sum of its proper divisors (1).

41024341153 is an equidigital number, since it uses as much as digits as its factorization.

41024341153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 41024341153 its reverse (35114342014), we get a palindrome (76138683167).

The spelling of 41024341153 in words is "forty-one billion, twenty-four million, three hundred forty-one thousand, one hundred fifty-three".