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4103437120037 is a prime number
BaseRepresentation
bin111011101101100111111…
…010010111001000100101
3112112021200120212211110222
4323231213322113020211
51014212314400320122
612421032030254125
7602314666010543
oct73554772271045
915467616784428
104103437120037
111342292306942
12563334957345
13239c4c7299c8
14102870a70d93
1571b16d30b42
hex3bb67e97225

4103437120037 has 2 divisors, whose sum is σ = 4103437120038. Its totient is φ = 4103437120036.

The previous prime is 4103437120033. The next prime is 4103437120103. The reversal of 4103437120037 is 7300217343014.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2276314492516 + 1827122627521 = 1508746^2 + 1351711^2 .

It is a cyclic number.

It is not a de Polignac number, because 4103437120037 - 22 = 4103437120033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4103437119979 and 4103437120006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4103437120031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2051718560018 + 2051718560019.

It is an arithmetic number, because the mean of its divisors is an integer number (2051718560019).

Almost surely, 24103437120037 is an apocalyptic number.

It is an amenable number.

4103437120037 is a deficient number, since it is larger than the sum of its proper divisors (1).

4103437120037 is an equidigital number, since it uses as much as digits as its factorization.

4103437120037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 42336, while the sum is 35.

The spelling of 4103437120037 in words is "four trillion, one hundred three billion, four hundred thirty-seven million, one hundred twenty thousand, thirty-seven".