Base | Representation |
---|---|
bin | 10010101010010100100011… |
… | …10011111110111011011111 |
3 | 12101022001112200201110020222 |
4 | 21111022101303332323133 |
5 | 20334320340322310112 |
6 | 223135534233231555 |
7 | 11433536210415101 |
oct | 1125122163767337 |
9 | 171261480643228 |
10 | 41036563869407 |
11 | 12091566535257 |
12 | 47291b22625bb |
13 | 19b8967a7c492 |
14 | a1c2749d9571 |
15 | 4b26c6477372 |
hex | 255291cfeedf |
41036563869407 has 4 divisors (see below), whose sum is σ = 41037198399120. Its totient is φ = 41035929339696.
The previous prime is 41036563869403. The next prime is 41036563869419. The reversal of 41036563869407 is 70496836563014.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 41036563869407 - 22 = 41036563869403 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 41036563869407.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41036563869401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 317167838 + ... + 317297195.
It is an arithmetic number, because the mean of its divisors is an integer number (10259299599780).
Almost surely, 241036563869407 is an apocalyptic number.
41036563869407 is a deficient number, since it is larger than the sum of its proper divisors (634529713).
41036563869407 is an equidigital number, since it uses as much as digits as its factorization.
41036563869407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 634529712.
The product of its (nonzero) digits is 78382080, while the sum is 62.
The spelling of 41036563869407 in words is "forty-one trillion, thirty-six billion, five hundred sixty-three million, eight hundred sixty-nine thousand, four hundred seven".
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