Base | Representation |
---|---|
bin | 111011101110001001100… |
… | …010111101110100111101 |
3 | 112112100010220200212002121 |
4 | 323232021202331310331 |
5 | 1014214443330144123 |
6 | 12421204025122541 |
7 | 602334660300040 |
oct | 73561142756475 |
9 | 15470126625077 |
10 | 4104001412413 |
11 | 1342551896081 |
12 | 563471929451 |
13 | 23a00c602716 |
14 | 1028c59a0c57 |
15 | 71b4b64875d |
hex | 3bb898bdd3d |
4104001412413 has 32 divisors (see below), whose sum is σ = 4974157520640. Its totient is φ = 3305479864320.
The previous prime is 4104001412411. The next prime is 4104001412417. The reversal of 4104001412413 is 3142141004014.
4104001412413 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 4104001412413 - 21 = 4104001412411 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4104001412411) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 505228170 + ... + 505236292.
It is an arithmetic number, because the mean of its divisors is an integer number (155442422520).
Almost surely, 24104001412413 is an apocalyptic number.
It is an amenable number.
4104001412413 is a deficient number, since it is larger than the sum of its proper divisors (870156108227).
4104001412413 is a wasteful number, since it uses less digits than its factorization.
4104001412413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14437.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 4104001412413 its reverse (3142141004014), we get a palindrome (7246142416427).
The spelling of 4104001412413 in words is "four trillion, one hundred four billion, one million, four hundred twelve thousand, four hundred thirteen".
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