Search a number
-
+
410412140214133 is a prime number
BaseRepresentation
bin101110101010001001000010…
…1110101000011011101110101
31222211011000110201000111221111
41131110102011311003131311
5412243143030343323013
64012512422343115021
7152306204300316151
oct13524220565033565
91884130421014844
10410412140214133
111098518a1801632
123a044757442a71
131480091122ca65
14734c0a7016061
15326ab6568573d
hex1754485d43775

410412140214133 has 2 divisors, whose sum is σ = 410412140214134. Its totient is φ = 410412140214132.

The previous prime is 410412140214091. The next prime is 410412140214151. The reversal of 410412140214133 is 331412041214014.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 322745285102769 + 87666855111364 = 17965113^2 + 9363058^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-410412140214133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 410412140214095 and 410412140214104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (410412147214133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205206070107066 + 205206070107067.

It is an arithmetic number, because the mean of its divisors is an integer number (205206070107067).

Almost surely, 2410412140214133 is an apocalyptic number.

It is an amenable number.

410412140214133 is a deficient number, since it is larger than the sum of its proper divisors (1).

410412140214133 is an equidigital number, since it uses as much as digits as its factorization.

410412140214133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 410412140214133 its reverse (331412041214014), we get a palindrome (741824181428147).

The spelling of 410412140214133 in words is "four hundred ten trillion, four hundred twelve billion, one hundred forty million, two hundred fourteen thousand, one hundred thirty-three".