Base | Representation |
---|---|
bin | 111011101110100001010… |
… | …011011101010011010011 |
3 | 112112101011200201012202122 |
4 | 323232201103131103103 |
5 | 1014221302400001321 |
6 | 12421311344204455 |
7 | 602350600240430 |
oct | 73564123352323 |
9 | 15471150635678 |
10 | 4104400000211 |
11 | 1342736886a85 |
12 | 56356330972b |
13 | 23a07406b2a4 |
14 | 1029228b8b87 |
15 | 71b7162d8ab |
hex | 3bba14dd4d3 |
4104400000211 has 8 divisors (see below), whose sum is σ = 4706752221024. Its totient is φ = 3506050120320.
The previous prime is 4104400000187. The next prime is 4104400000223. The reversal of 4104400000211 is 1120000044014.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4104400000211 - 26 = 4104400000147 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4104400000211.
It is not an unprimeable number, because it can be changed into a prime (4104400000411) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1000583030 + ... + 1000587131.
It is an arithmetic number, because the mean of its divisors is an integer number (588344027628).
Almost surely, 24104400000211 is an apocalyptic number.
4104400000211 is a deficient number, since it is larger than the sum of its proper divisors (602352220813).
4104400000211 is a wasteful number, since it uses less digits than its factorization.
4104400000211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2001170461.
The product of its (nonzero) digits is 128, while the sum is 17.
Adding to 4104400000211 its reverse (1120000044014), we get a palindrome (5224400044225).
The spelling of 4104400000211 in words is "four trillion, one hundred four billion, four hundred million, two hundred eleven", and thus it is an aban number.
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