Base | Representation |
---|---|
bin | 100110001110011010… |
… | …011111010000110011 |
3 | 10220221102112221122112 |
4 | 212032122133100303 |
5 | 1133024231423011 |
6 | 30504431355535 |
7 | 2652052235531 |
oct | 461632372063 |
9 | 126842487575 |
10 | 41044014131 |
11 | 1645230433a |
12 | 7b55682bab |
13 | 3b414603c3 |
14 | 1db50d5151 |
15 | 11034ae58b |
hex | 98e69f433 |
41044014131 has 2 divisors, whose sum is σ = 41044014132. Its totient is φ = 41044014130.
The previous prime is 41044014127. The next prime is 41044014139. The reversal of 41044014131 is 13141044014.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41044014131 - 22 = 41044014127 is a prime.
It is a super-2 number, since 2×410440141312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 41044014097 and 41044014106.
It is not a weakly prime, because it can be changed into another prime (41044014139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20522007065 + 20522007066.
It is an arithmetic number, because the mean of its divisors is an integer number (20522007066).
Almost surely, 241044014131 is an apocalyptic number.
41044014131 is a deficient number, since it is larger than the sum of its proper divisors (1).
41044014131 is an equidigital number, since it uses as much as digits as its factorization.
41044014131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 41044014131 its reverse (13141044014), we get a palindrome (54185058145).
The spelling of 41044014131 in words is "forty-one billion, forty-four million, fourteen thousand, one hundred thirty-one".
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