Base | Representation |
---|---|
bin | 111011101110101010011… |
… | …011100101001100111111 |
3 | 112112101120100211202000221 |
4 | 323232222123211030333 |
5 | 1014222111044442141 |
6 | 12421334454202211 |
7 | 602354436622426 |
oct | 73565233451477 |
9 | 15471510752027 |
10 | 4104553124671 |
11 | 134280526271a |
12 | 5635a6653367 |
13 | 23a0999c238c |
14 | 102938d782bd |
15 | 71b7ecc8bd1 |
hex | 3bbaa6e533f |
4104553124671 has 2 divisors, whose sum is σ = 4104553124672. Its totient is φ = 4104553124670.
The previous prime is 4104553124611. The next prime is 4104553124719. The reversal of 4104553124671 is 1764213554014.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4104553124671 - 231 = 4102405641023 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4104553124611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2052276562335 + 2052276562336.
It is an arithmetic number, because the mean of its divisors is an integer number (2052276562336).
Almost surely, 24104553124671 is an apocalyptic number.
4104553124671 is a deficient number, since it is larger than the sum of its proper divisors (1).
4104553124671 is an equidigital number, since it uses as much as digits as its factorization.
4104553124671 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 403200, while the sum is 43.
Adding to 4104553124671 its reverse (1764213554014), we get a palindrome (5868766678685).
It can be divided in two parts, 4104553 and 124671, that added together give a palindrome (4229224).
The spelling of 4104553124671 in words is "four trillion, one hundred four billion, five hundred fifty-three million, one hundred twenty-four thousand, six hundred seventy-one".
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