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41100004313 = 62636562351
BaseRepresentation
bin100110010001110000…
…000100101111011001
310221002022220112201222
4212101300010233121
51133133100114223
630514151421425
72653332162314
oct462160045731
9127068815658
1041100004313
1116480976615
127b70384875
133b4cc351a4
141dbc70b97b
15110836e0c8
hex991c04bd9

41100004313 has 4 divisors (see below), whose sum is σ = 41106572928. Its totient is φ = 41093435700.

The previous prime is 41100004273. The next prime is 41100004333. The reversal of 41100004313 is 31340000114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 41100004313 - 210 = 41100003289 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41100004291 and 41100004300.

It is not an unprimeable number, because it can be changed into a prime (41100004333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3274913 + ... + 3287438.

It is an arithmetic number, because the mean of its divisors is an integer number (10276643232).

Almost surely, 241100004313 is an apocalyptic number.

It is an amenable number.

41100004313 is a deficient number, since it is larger than the sum of its proper divisors (6568615).

41100004313 is an equidigital number, since it uses as much as digits as its factorization.

41100004313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6568614.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 41100004313 its reverse (31340000114), we get a palindrome (72440004427).

The spelling of 41100004313 in words is "forty-one billion, one hundred million, four thousand, three hundred thirteen".

Divisors: 1 6263 6562351 41100004313